Solving brackets does not include forced distribution

Yes it does! 😂

Juxtaposition means multiplication,

No, it doesn't. A Product is the result of Multiplication. If a=2 and b=3, axb=ab, 2x3=6, axb=2x3, ab=6. 3(x-y) is 1 term, 3x-3y is 2 terms...

as such, 2(3+5)² is the same as 2*(3+5)²

No it isn't. 2(3+5)² is 1 term, 2x(3+5)² is 2 terms

so once the brackets result in 8

They don't - you still have an undistributed coefficient, 2(8)

they’re solved

Not until you've Distributed and Simplified they aren't

Distribution needs to happen if you want to remove the brackets

if you want to remove the brackets, YES, that's what the Brackets step is for, duh! 😂 The textbook above says to Distribute first, then Simplify.

while there are still multiple terms inside

As in 2(8)=(2x8) and 2(3+5)=(6+10) is multiple Terms inside 😂

it’s still a part of the multiplication

Nope! The Brackets step, duh 😂 You cannot progress until all Brackets have been removed

which has higher priority.

It doesn't have a higher priority than Brackets! 🤣

Your whole argument hangs on the misinterpretation of textbooks

says person who can't cite any textbooks that agree with them, wrongly calls Products "Multiplication", and claimed that I invented a rule that is in an 1898 textbook! 🤣

This is what it feels like to argue against Bible fanatics

says the Bible fanatic, who in this case can't even show me what it says in The Bible (Maths textbooks) that agrees with them 😂

provide me a solver that says 2(3+5)² is 256 and you’ve won, it’s so easy no?

provide me a Maths textbook that says 8/2(1+3)=16 and you’ve won, it’s so easy no? 🤣

And in the meantime, here's one saying it's 1, because x(x-1) is a single Term...